Verified Solution • 2025–26 Session
moderate
QJEEM06Ch2435: JEE Main 2006 Chemistry - Class 11 JEEM06Ch2435 Solution: The decreasing values of bond angles from NH 3 (106 o ) to SbH…
The decreasing values of bond angles from NH3 (106o) to SbH3 (91o ) down group-15 of the periodic table is due to
Multiple Choice Options
- A increasing bp-bp repulsion
- B increasing p-orbital character in sp3
- C decreasing lp-bp repulsion
- D decreasing electronegativity
Step-by-Step Verified Solution
Nitrogen(N) atom is smaller in size so it's lone pair is relatively unstable. That is why repulsion between lone pairs present on nitrogen atom and bonded pairs of electrons is relatively high.
But size of Sb is more so its lone pair is relatively stable. That is why it does not want to perticipate in bond pair lone pair repulsion and decreases lp-bp repulsion.
But size of Sb is more so its lone pair is relatively stable. That is why it does not want to perticipate in bond pair lone pair repulsion and decreases lp-bp repulsion.