Verified Solution • 2025–26 Session moderate

QJEEM06Ch13b1: JEE Main 2006 Chemistry - Class 11 JEEM06Ch13b1 Solution: Phosphorus pentachloride dissociates as follows, in a closed…

Phosphorus pentachloride dissociates as follows, in a closed reaction vessel
PCl5 (g) ⇋\leftrightharpoons PCl3 (g) + Cl2 (g)
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl5 is x, the partial pressure of PCl3 will be

Multiple Choice Options

  • A (xx+1)P\left( {{x \over {x + 1}}} \right)P
  • B (2x1−x)P\left( {{2x \over {1 - x}}} \right)P
  • C (xx−1)P\left( {{x \over {x - 1}}} \right)P
  • D (x1−x)P\left( {{x \over {1 - x}}} \right)P

Step-by-Step Verified Solution

PCl5(g)1−x ⇌ PCl3(g)x  +  Cl2(g)x\mathop {PC{l_5}\left( g \right)}\limits_{1 - x} \mathop {\,\rightleftharpoons\,PC{l_3}\left( g \right)}\limits_x \,\, + \,\,\mathop {C{l_2}\left( g \right)}\limits_x

Total moles after dissociation

1−x+x+x=1+x1 - x + x + x = 1 + x

PPCl3={P_{PC{l_3}}} = mole fraction of PCl3×PCl{}_3 \times Total pressure

=(x1+x)P= \left( {{x \over {1 + x}}} \right)P

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