QJEEM06Ch0ef4: JEE Main 2006 Chemistry - Class 12 JEEM06Ch0ef4 Solution: The “spin-only” magnetic moment [in units of Bohr magneton, (µ…

Question

Verified Solution • 2025–26 Session moderate

The “spin-only” magnetic moment [in units of Bohr magneton, (µ_B)] of Ni²⁺ in aqueous solution would be : (Atomic number of Ni = 28)

Accepted Answer

The number of unpaired electrons in

N i^{2 +} (a q) = 2

Water is weak ligand hence no pairing will take place spin magnetic moment

\begin{aligned} = \sqrt{n (n + 2)} = \sqrt{2 (2 + 2)} \\ = \sqrt{8} = 2.82 \end{aligned}

Step-by-Step Verified Solution