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QJEEM05Ma1f73: JEE Main 2005 Mathematics - Class 11 JEEM05Ma1f73 Solution: If and , then lies on :

If  ω=zz−13i \,\omega = {z \over {z - {1 \over 3}i}}\, and ∣ω∣=1\left| \omega \right| = 1 , then zz lies on :

Multiple Choice Options

  • A an ellipse
  • B a circle
  • C a straight line
  • D a parabola

Step-by-Step Verified Solution

Given  ω=zz−13i \,\omega = {z \over {z - {1 \over 3}i}}\, and ∣ω∣=1\left| \omega \right| = 1

∴\therefore ∣z∣∣z−13i∣=∣ω∣{{\left| z \right|} \over {\left| {z - {1 \over {\sqrt 3 }}i} \right|}} = \left| \omega \right|

⇒\Rightarrow ∣z∣∣z−13i∣=1{{\left| z \right|} \over {\left| {z - {1 \over {\sqrt 3 }}i} \right|}} = 1

⇒\Rightarrow ∣z∣=∣z−13i∣\left| z \right| = \left| {z - {1 \over {\sqrt 3 }}i} \right| ..........equation (1)

∣z∣\left| z \right| represent distance of zz from point (0, 0) and

∣z−13i∣\left| {z - {1 \over {\sqrt 3 }}i} \right| represent distance of zz from point (0,13)\left( {0,{1 \over {\sqrt 3 }}} \right) .

According to the equation (1) the distance of zz from point (0, 0) and (0,13)\left( {0,{1 \over {\sqrt 3 }}} \right) is equal. Only if z is on a straight line then it will be equal distance from the both the points. AIEEE 2005 Mathematics - Complex Numbers Question 167 English Explanation

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