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QJEEM05Che0e3: JEE Main 2005 Chemistry - Class 11 JEEM05Che0e3 Solution: If the bond dissociation energies of XY, X 2 and Y 2 (all…

If the bond dissociation energies of XY, X2 and Y2 (all diatomic molecules) are in the ratio of 1:1:0.5 and ΔHf for the formation of XY is -200 kJ mole-1. The bond dissociation energy of X2 will be :

Multiple Choice Options

  • A 100 kJ mol-1
  • B 200 kJ mol-1
  • C 300 kJ mol-1
  • D 800 kJ mol-1

Step-by-Step Verified Solution

X2+Y2→2XY, ΔH=2(−200).

Let x be the bond dissociation energy of X2.

Then ΔH=−400

=ξx−x+ξy−y−2ξx−y

=x+0.5x−2x

=−0.5x

or x=4000.5=800kJmol−1

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