QJEEM05Ch27e3: JEE Main 2005 Chemistry - Class 11 JEEM05Ch27e3 Solution: Consider the reaction: N 2 + 3H 2 2NH 3 carried out at constant …

Question

Verified Solution • 2025–26 Session moderate

Consider the reaction: N₂ + 3H₂

\to

2NH₃ carried out at constant temperature and pressure. If

\Delta H

and

\Delta U

are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

Accepted Answer

\Delta H = \Delta U + \Delta nRT

for

\,\,\,{N_2} + 3{H_2} \to 2N{H_3}

\,\,\,\Delta {n_g} = 2 - 4 = - 2

\therefore

\,\,\,\Delta H = \Delta U - 2RT\,\,\,

or

\,\,\,\Delta U = \Delta H + 2RT

\therefore

\,\,\,\Delta U &gt; \Delta H

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