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QJEEM04Chd717: JEE Main 2004 Chemistry - Class 12 JEEM04Chd717 Solution: Consider the following E o values = 0.77 V; = -0.14 V Under…

Consider the following Eo values

EFe3+/Fe2+oE_{F{e^{3 + }}/F{e^{2 + }}}^o = 0.77 V;

ESn2+/SnoE_{S{n^{2 + }}/S{n}}^o = -0.14 V

Under standard conditions the potential for the reaction

Sn(s) + 2Fe3+(aq) →\to 2Fe2+(aq) + Sn2+(aq) is :

Multiple Choice Options

  • A 1.68 V
  • B 0.63 V
  • C 0.91 V
  • D 1.40 V

Step-by-Step Verified Solution

Fe3++e−→Fe2+ΔG∘F{e^{3 + }} + {e^ - } \to F{e^{2 + }}\Delta {G^ \circ }

          =−1×F×0.77\,\,\,\,\,\,\,\,\,\, = - 1 \times F \times 0.77

Sn2++2e−→Sn(s)ΔG∘S{n^{2 + }} + 2{e^ - } \to Sn\left( s \right)\Delta {G^ \circ }

=−2×F(−0.14)= - 2 \times F\left( { - 0.14} \right)

Sn(s)+2Fe3+(aq)Sn\left( s \right) + 2F{e^{3 + }}\left( {aq} \right)

          →2Fe2+(aq)+Sn2+(aq)\,\,\,\,\,\,\,\,\,\, \to 2F{e^{2 + }}\left( {aq} \right) + S{n^{2 + }}\left( {aq} \right)

∴\therefore Standard potential for the given reaction

or Ecello=ESn/Sn2+o+EFe3+/Fe2+0E_{cell}^o = E_{Sn/S{n^{2 + }}}^o + E_{F{e^{3 + }}/F{e^{2 + }}}^0

=0.14+0.77=0.91 V= 0.14 + 0.77 = 0.91\,V

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