Verified Solution • 2025–26 Session moderate

QJEEM04Chc598: JEE Main 2004 Chemistry - Class 11 JEEM04Chc598 Solution: The molar solubility (in ol L -1 ) of a sparingly soluble salt…

The molar solubility (in ol L-1) of a sparingly soluble salt MX4 is "s". The corresponding solubility product is Ksp. 's' is given in term of Ksp by the relation :

Multiple Choice Options

  • A s = (256 Ksp)1/5
  • B s = (128 Ksp)1/4
  • C s = ( Ksp / 128)1/4
  • D s = (Ksp / 256)1/5

Step-by-Step Verified Solution

MX4⇌ M4+S       +4X−4SM{X_4}\rightleftharpoons\,\mathop {{M^{4 + }}}\limits_{S\,\,\,\,\,\,\,} + \mathop {4{X^ - }}\limits_{4S}

Ksp=[s][4s]4=256 s5{K_{sp}} = \left[ s \right]{\left[ {4s} \right]^4} = 256\,{s^5}

∴\therefore      s=(Ksp256)1/5\,\,\,\,\,s = {\left( {{{{K_{sp}}} \over {256}}} \right)^{1/5}}

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