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QJEEM04Chc45d: JEE Main 2004 Chemistry - Class 12 JEEM04Chc45d Solution: The standard e.m.f of a cell, involving one electron change is…

The standard e.m.f of a cell, involving one electron change is found to be 0.591 V at 25oC. The equilibrium constant of the reaction is (F = 96,500 C mol-1: R = 8.314 JK-1 mol-1)

Multiple Choice Options

  • A 1.0 ×\times 101
  • B 1.0 ×\times 1030
  • C 1.0 ×\times 1010
  • D 1.0 ×\times 105

Step-by-Step Verified Solution

Ecello=Ecello−0.059nlog⁡ KcE_{cell}^o = E_{cell}^o - {{0.059} \over n}\log \,{K_c}

or       \,\,\,\,\,\, 0=0.591−0.05911log⁡Kc0 = 0.591 - {{0.0591} \over 1}\log {K_c}

or       \,\,\,\,\,\, log⁡ Kc=0.5910.0591=10\log \,{K_c} = {{0.591} \over {0.0591}} = 10

or       \,\,\,\,\,\, Kc=1×1010{K_c} = 1 \times {10^{10}}

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