QJEEM04Ch6a68: JEE Main 2004 Chemistry - Class 12 JEEM04Ch6a68 Solution: The half – life of a radioisotope is four hours. If the initial …

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The half – life of a radioisotope is four hours. If the initial mass of the isotope was 200 g, the mass remaining after 24 hours undecayed is

Accepted Answer

N_{t} = N_{0} {(\frac{1}{2})}^{n}

where

n

is number of half life periods.

n = \frac{T o t a l t i m e}{h a l f l i f e} = \frac{24}{4} = 6

∴

N_{t} = 200 {(\frac{1}{2})}^{6} = 3.125 g .

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