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QJEEM04Ch5b43: JEE Main 2004 Chemistry - Class 12 JEEM04Ch5b43 Solution: Which one of the following aqueous solutions will exhibit…

Which one of the following aqueous solutions will exhibit highest boiling point?

Multiple Choice Options

  • A 0.01 M Na2SO4
  • B 0.015 M glucose
  • C 0.015 M urea
  • D 0.01 M KNO3

Step-by-Step Verified Solution

As     ΔTbb=Tb−Tbo\,\,\,\,\Delta {T_b}^b = {T_b} - {T_b}^o

Where Tb=b.pt{T_b} = b.pt of solution

Tbo=b.ptT_b^o = b.pt of solvent or

Tb=Tbo+ΔTb{T_b} = T_b^o + \Delta {T_b}

NOTE : Elevation in boiling point is a colligative property, which depends upon the no. of particles. Thus greater the number of particles, greater is it elevation and hence greater will be its boiling point. </mo></mrow><mi>N</mi><mrowdata−mjx−texclass="ORD"><msub><mi>a</mi><mn>2</mn></msub></mrow><mi>S</mi><mrowdata−mjx−texclass="ORD"><msub><mi>O</mi><mn>4</mn></msub></mrow><mstylescriptlevel="0"><mspacewidth="0.167em"></mspace></mstyle><mstylescriptlevel="0"><mspacewidth="0.167em"></mspace></mstyle><modata−mjx−alternate="1"stretchy="false">⇌</mo><mstylescriptlevel="0"><mspacewidth="0.167em"></mspace></mstyle><mstylescriptlevel="0"><mspacewidth="0.167em"></mspace></mstyle><mn>2</mn><mi>N</mi><mrowdata−mjx−texclass="ORD"><msup><mi>a</mi><mo>+</mo></msup></mrow><mo>+</mo><mi>S</mi><msubsup><mi>O</mi><mn>4</mn><mrowdata−mjx−texclass="ORD"><mn>2</mn><mo>−</mo></mrow></msubsup></math></mjx−assistive−mml></mjx−container></mjx−assistive−mml></mjx−container></mjx−assistive−mml></mjx−container></mo></mrow><mi>N</mi><mrow data-mjx-texclass="ORD"><msub><mi>a</mi><mn>2</mn></msub></mrow><mi>S</mi><mrow data-mjx-texclass="ORD"><msub><mi>O</mi><mn>4</mn></msub></mrow><mstyle scriptlevel="0"><mspace width="0.167em"></mspace></mstyle><mstyle scriptlevel="0"><mspace width="0.167em"></mspace></mstyle><mo data-mjx-alternate="1" stretchy="false">⇌</mo><mstyle scriptlevel="0"><mspace width="0.167em"></mspace></mstyle><mstyle scriptlevel="0"><mspace width="0.167em"></mspace></mstyle><mn>2</mn><mi>N</mi><mrow data-mjx-texclass="ORD"><msup><mi>a</mi><mo>+</mo></msup></mrow><mo>+</mo><mi>S</mi><msubsup><mi>O</mi><mn>4</mn><mrow data-mjx-texclass="ORD"><mn>2</mn><mo>−</mo></mrow></msubsup></math></mjx-assistive-mml></mjx-container></mjx-assistive-mml></mjx-container></mjx-assistive-mml></mjx-container>
Since Na2SO4  N{a_2}S{O_4}\,\, has maximum number of particles (3)(3) hence has maximum boiling point.

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