QJEEM04Ch27ec: JEE Main 2004 Chemistry - Class 11 JEEM04Ch27ec Solution: Which one of the following has the regular tetrahedral…

Regular Tetrahedral structure is possible in sp³ hybridization where central atom has 4 bond pair and no lone pair.

(a)   XeF₄  is sp³d² hybridised and structure is square planar.



(b)   [Ni(CN)₄] ^{$-$ 2} is coordinate compound and oxidation number of Ni is +2.

Electronic configuration of Ni⁺² is $=$ [Ar]3d⁸



But because of CN ^$-$ ion which is a strong field ligand , it can perform pairing of electron.



And the structure of dsp² hybridization is square planar.



(C) $\,\,\,\,$ BF $_4^ -$ , 4 bond pair present so angle is 109^o 28^' and sp³ hybridised. So structure is regular tetrahedral.



(d)   

SF₄ is sp³d hybridised and structure is see-saw.