QJEEM04Ch0a69: JEE Main 2004 Chemistry - Class 12 JEEM04Ch0a69 Solution: The limiting molar conductivities Λ° for NaCl, KBr and KCl are…

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The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm² mol^-1 respectively. The Λ° for NaBr is

Accepted Answer

{A^ \circ }Nacl = {\lambda ^ \circ }N{a^ + } + \lambda C{l^ - }\,\,\,\,\,\,\,\,\,\,\,...\left( i \right)

{A^ \circ }KBr = {\lambda ^ \circ }{K^ + } + \lambda Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {ii} \right)

{A^ \circ }KCl = {\lambda ^ \circ }{K^ + } + \lambda C{l^ - }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {iii} \right)

operating

(i)+(ii)-(iii)

{A^ \circ }NaBr = {\lambda ^ \circ }N{a^ + } + {\lambda ^ \circ }B{r^ - }

= 126 + 152 - 150

= 128\,\,\,S\,c{m^2}\,mo{l^{ - 1}}

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