Verified Solution • 2025–26 Session moderate

QJEEM03Chf46f: JEE Main 2003 Chemistry - Class 12 JEEM03Chf46f Solution: The radius of La 3+ (Atomic number of La = 57) is 1.06 Å. Which …

The radius of La3+ (Atomic number of La = 57) is 1.06 Å. Which one of the following given values will be closest to the radius of Lu3+ (Atomic number of Lu = 71) ?

Multiple Choice Options

  • A 1.60 Å
  • B 1.40 Å
  • C 0.85 Å
  • D 1.60 Å

Step-by-Step Verified Solution

Ionic radili ∝1z\propto {1 \over z}

Thus, z2z1⇒1.06(Ionic   radii   of  Lu3+)=7157{{{z_2}} \over {{z_1}}} \Rightarrow {{1.06} \over {\left( {Ionic\,\,\,radii\,\,\,of\,\,L{u^{3 + }}} \right)}} = {{71} \over {57}}

⇒   \Rightarrow \,\,\, Ionic radii of Lu3+=0.85 A∘L{u^{3 + }} = 0.85\,\mathop A\limits^ \circ

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