Verified Solution • 2025–26 Session moderate

QJEEM03Chb4aa: JEE Main 2003 Chemistry - Class 12 JEEM03Chb4aa Solution: For a cell reaction involving a two-electron change, the…

For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be 0.295 V at 25oC. The equilibrium constant of the reaction at 25oC will be

Multiple Choice Options

  • A 29.5 ×\times 10-2
  • B 10
  • C 1 ×\times 1010
  • D 1 ×\times 10-10

Step-by-Step Verified Solution

The equlibrium constant is released to the standard emf of cell by the expression

log⁡ K=E∘cell×n0.059\log \,K = {E^ \circ }_{cell} \times {n \over {0.059}}

=0.295×20.059= 0.295 \times {2 \over {0.059}}

log⁡ K=59059=10\log \,K = {{590} \over {59}} = 10

or      K=1×1010\,\,\,\,\,K = 1 \times {10^{10}}

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