Verified Solution • 2025–26 Session
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QJEEM03Ch097e: JEE Main 2003 Chemistry - Class 12 JEEM03Ch097e Solution: The radionucleide 90 234 T h undergoes two successive β -decays …
The radionucleide undergoes two successive -decays followed by one -decay. The atomic number and the mass number respectively of the resulting radionucleide are
Multiple Choice Options
- A 94 and 230
- B 90 and 230
- C 92 and 230
- D 92 and 234