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QJEEM03Ch097e: JEE Main 2003 Chemistry - Class 12 JEEM03Ch097e Solution: The radionucleide 90 234 T h undergoes two successive β -decays …

The radionucleide 90234Th undergoes two successive β -decays followed by one α-decay. The atomic number and the mass number respectively of the resulting radionucleide are

Multiple Choice Options

  • A 94 and 230
  • B 90 and 230
  • C 92 and 230
  • D 92 and 234

Step-by-Step Verified Solution

90234Th⟶−β91234X⟶−β92234Th⟶−α90230Th

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