Verified Solution • 2025–26 Session moderate

QJEEM02Mae607: JEE Main 2002 Physics - Class 11 JEEM02Mae607 Solution: If and the angle between and is then is equal to :

If ∣a→∣=4,∣b→∣=2\left| {\overrightarrow a } \right| = 4,\left| {\overrightarrow b } \right| = 2 and the angle between a→{\overrightarrow a } and b→{\overrightarrow b } is π/6\pi /6 then (a→×b→)2{\left( {\overrightarrow a \times \overrightarrow b } \right)^2} is equal to :

Multiple Choice Options

  • A 4848
  • B 1616
  • C a→\overrightarrow a
  • D none of these

Step-by-Step Verified Solution

(a→×b→)2=∣a→∣2∣b→∣2  sin⁡2π6{\left( {\overrightarrow a \times \overrightarrow b } \right)^2} = {\left| {\overrightarrow a } \right|^2}{\left| {\overrightarrow b } \right|^2}\,\,{\sin ^2}{\pi \over 6}

=16×4×14=16= 16 \times 4 \times {1 \over 4} = 16

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