Verified Solution • 2025–26 Session moderate

QJEEM02Ma1e42: JEE Main 2002 Physics - Class 11 JEEM02Ma1e42 Solution: If the vectors and from the sides and respectively of a…

If the vectors a→,b→\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}} and c→\overrightarrow{\mathbf{c}} from the sides BC,CAB C, C A and ABA B respectively of a triangle ABCA B C , then :

Multiple Choice Options

  • A a→⋅b→=b→⋅c→=c→⋅b→=0\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \cdot \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \cdot \overrightarrow{\mathbf{b}}=0
  • B a→×b→=b→×c→=c→×a→\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \times \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}}
  • C a→⋅b→=b→⋅c→=c→⋅a→=0\overrightarrow{\mathbf{a}} \cdot \overrightarrow{\mathbf{b}}=\overrightarrow{\mathbf{b}} \cdot \overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{c}} \cdot \overrightarrow{\mathbf{a}}=0
  • D a→×a→+a→×c→+c→×a→=0→\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{a}} \times \overrightarrow{\mathbf{c}}+\overrightarrow{\mathbf{c}} \times \overrightarrow{\mathbf{a}}=\overrightarrow{\mathbf{0}}

Step-by-Step Verified Solution

If a→,b→\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}} and c→\overrightarrow{\mathbf{c}} are the sides of a\mathbf{a} triangle, then

a→+b→+c→=0→\overrightarrow{\mathbf{a}}+\overrightarrow{\mathbf{b}}+\overrightarrow{\mathbf{c}}=\overrightarrow{\mathbf{0}}

Since,

a⃗+b⃗+c⃗amp;=0→a⃗+b⃗amp;=−c⃗\begin{aligned}\vec{a}+\vec{b}+\vec{c} & =\overrightarrow{0} \\\\\vec{a}+\vec{b} & =-\vec{c}\end{aligned}

⇒amp;(a⃗+b⃗)×c⃗=−c⃗×c⃗⇒amp;a⃗×c⃗+b⃗×c⃗=0→⇒amp;b⃗×c⃗=c⃗×a⃗ Similarly, amp;a⃗×b⃗=b⃗×c⃗ Hence, amp;a⃗×b⃗=b⃗×c⃗=c⃗×a⃗\begin{array}{ll}\Rightarrow & (\vec{a}+\vec{b}) \times \vec{c}=-\vec{c} \times \vec{c} \\\\\Rightarrow & \vec{a} \times \vec{c}+\vec{b} \times \vec{c}=\overrightarrow{0} \\\\\Rightarrow & \vec{b} \times \vec{c}=\vec{c} \times \vec{a} \\\\\text { Similarly, } & \vec{a} \times \vec{b}=\vec{b} \times \vec{c} \\\\\text { Hence, } & \vec{a} \times \vec{b}=\vec{b} \times \vec{c}=\vec{c} \times \vec{a}\end{array}

Related Learning Resources & Exam Preparation