QJEEM02Chde61: JEE Main 2002 Chemistry - Class 12 JEEM02Chde61 Solution: Oxidation number of Cl in CaOCl 2 (bleaching powder) is :

Question

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Oxidation number of Cl in CaOCl₂ (bleaching powder) is :

Accepted Answer

C a O C l_{2} -

or it can also be written as

C a \underset{x_{1}}{(O C l)} \underset{x_{2}}{C l}

hence oxidation no of

C l

in

O C l^{-}

is

\begin{aligned} - 2 + x_{2} = - 1 \\ x^{2} = 2 - 1 = + 1 \end{aligned}

now oxidation no. of another

C l

is

- 1

as it is present as

C l^{-} .

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