QJEEM02Chd7ad: JEE Main 2002 Chemistry - Class 12 JEEM02Chd7ad Solution: For the following cell with hydrogen electrodes at two…

Question

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For the following cell with hydrogen electrodes at two different pressure p₁ and p₂. What will be the emf for the given cell :

\begin{aligned} P t (H_{2}) | H^{+} (a q) | P t (H_{2}) \\ p_{1} 1 M p_{2} \end{aligned}

Accepted Answer

Oxidation half cell : -

H_{2} (g) \overset{}{⟶} 2 H^{+} (1 M) + 2 e^{-} . . . P_{1}

Reduction half cell

2 H^{+} (1 M) + 2 e^{-} \overset{}{⟶} H_{2} (g) . . . P_{2}

The net cell reaction

\underset{P_{1}}{H_{2}} (g) \overset{}{⟶} \underset{P_{2}}{H_{2}} (g)

E_{cell}^ \circ = 0.00\,V

\,\,\,\,\,

n=2

\therefore

\,\,\,\,

{E_{cell}} = E_{cell}^ \circ - {{RT} \over {nF}}{\log _c}K

= 0 - {{RT} \over {nF}}{\log _e}{{{P_2}} \over {{P_1}}}

or

\,\,\,\,{E_{cell}} = {{RT} \over {2F}}{\log _e}{{{P_1}} \over {{P_2}}}

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