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QJEEAdv24Ph3865: JEE Advanced 2024 Physics - Class 12 JEEAdv24Ph3865 Solution: Two equilateral-triangular prisms and are kept with their sides …

Two equilateral-triangular prisms P1\mathrm{P}_1 and P2\mathrm{P}_2 are kept with their sides parallel to each other, in vacuum, as shown in the figure. A light ray enters prism P1\mathrm{P}_1 at an angle of incidence θ\theta such that the outgoing ray undergoes minimum deviation in prism P2\mathrm{P}_2 . If the respective refractive indices of P1\mathrm{P}_1 and P2\mathrm{P}_2 are 32\sqrt{\frac{3}{2}} and 3\sqrt{3} , then θ=sin⁡−1[32sin⁡(πβ)]\theta=\sin ^{-1}\left[\sqrt{\frac{3}{2}} \sin \left(\frac{\pi}{\beta}\right)\right] , where the value of β\beta is ____.

JEE Advanced 2024 Paper 2 Online Physics - Geometrical Optics Question 3 English

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JEE Advanced 2024 Paper 2 Online Physics - Geometrical Optics Question 3 English Explanation

At surface BC

32sin⁡r2=3sin⁡3032sin⁡r2=32sinr2=12r2=45∘r1=60∘−45∘=15∘

At surface AB

1sin⁡θ=32sin⁡15∘θ=sin−1⁡[32sin⁡π12]β=12

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