QJEEAdv24Ma226b: JEE Advanced 2024 Mathematics - Class 12 JEEAdv24Ma226b Solution: Considering only the principal values of the inverse…

Question

Verified Solution • 2025–26 Session moderate

QJEEAdv24Ma226b: JEE Advanced 2024 Mathematics - Class 12 JEEAdv24Ma226b Solution: Considering only the principal values of the inverse…

Considering only the principal values of the inverse trigonometric functions, the value of

$\tan (\sin^{- 1} (\frac{3}{5}) - 2 \cos^{- 1} (\frac{2}{\sqrt{5}}))$

is

Multiple Choice Options

A $\frac{7}{24}$
B $\frac{-7}{24}$
C $\frac{-5}{24}$
D $\frac{5}{24}$

Related Learning Resources & Exam Preparation

JEE Advanced PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring

Accepted Answer

$\begin{aligned} \tan (\tan^{- 1} (\frac{3}{4}) - 2 \tan^{- 1} (\frac{1}{2})) \\ \tan (\tan^{- 1} (\frac{3}{4}) - \tan^{- 1} (\frac{2 \times \frac{1}{2}}{1 - \frac{1}{4}})) \\ \tan (\tan^{- 1} (\frac{3}{4}) - \tan^{- 1} (\frac{4}{3})) \\ \tan (\tan^{- 1} (\frac{3}{4} - \frac{4}{3})) \\ \frac{9 - 16}{24} = \frac{- 7}{24} \end{aligned}$

QJEEAdv24Ma226b: JEE Advanced 2024 Mathematics - Class 12 JEEAdv24Ma226b Solution: Considering only the principal values of the inverse…

Multiple Choice Options

Step-by-Step Verified Solution

Related Learning Resources & Exam Preparation