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QJEEAdv24Cheb0b: JEE Advanced 2024 Chemistry - Class 12 JEEAdv24Cheb0b Solution: Among , and , the total number of species isoelectronic with is …

Among V(CO)6,Cr(CO)5,Cu(CO)3,Mn(CO)5,Fe(CO)5,[Co(CO)3]3−,[Cr(CO)4]4−\mathrm{V}(\mathrm{CO})_6, \mathrm{Cr}(\mathrm{CO})_5, \mathrm{Cu}(\mathrm{CO})_3, \mathrm{Mn}(\mathrm{CO})_5, \mathrm{Fe}(\mathrm{CO})_5,\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-},\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-} , and Ir⁡(CO)3\operatorname{Ir}(\mathrm{CO})_3 , the total number of species isoelectronic with Ni(CO)4\mathrm{Ni}(\mathrm{CO})_4 is _________.

[Given, atomic number: V=23,Cr=24,Mn=25,Fe=26,Co=27,Ni=28,Cu=29,Ir=77\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27, \mathrm{Ni}=28, \mathrm{Cu}=29, \mathrm{Ir}=77 ]

Step-by-Step Verified Solution

amp; Total number of electron in Ni(CO)4=84amp; Species amp;amp; Total electron V(CO)6amp;−amp;107Cr(CO)5amp;−amp;94Cu(CO)3amp;−amp;71Mn(CO)5amp;−amp;95Fe(CO)5amp;−amp;96[Co(CO)3]3−amp;−amp;72[Cr(CO)4]4−amp;−amp;84Ir⁡(CO)3amp;−amp;119\begin{aligned}&\text { Total number of electron in } \mathrm{Ni}(\mathrm{CO})_4=84\\\\&\begin{array}{lll}\text { Species } & & \text { Total electron } \\\\\mathrm{V}(\mathrm{CO})_6 & - & 107 \\\\\mathrm{Cr}(\mathrm{CO})_5 & - & 94 \\\\\mathrm{Cu}(\mathrm{CO})_3 & - & 71 \\\\\mathrm{Mn}(\mathrm{CO})_5 & - & 95 \\\\\mathrm{Fe}(\mathrm{CO})_5 & - & 96 \\\\{\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-}} & - & 72 \\\\{\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-}} & - & 84 \\\\\operatorname{Ir}(\mathrm{CO})_3 & - & 119\end{array}\end{aligned}

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