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QJEEAdv24Chd1fb: JEE Advanced 2024 Chemistry - Class 11 JEEAdv24Chd1fb Solution: In the following reaction sequence, the major product is…

In the following reaction sequence, the major product P\mathbf{P} is formed.

JEE Advanced 2024 Paper 1 Online Chemistry - Hydrocarbons Question 1 English

Glycerol reacts completely with excess P\mathbf{P} in the presence of an acid catalyst to form Q\mathbf{Q} . Reaction of Q\mathbf{Q} with excess NaOH\mathrm{NaOH} followed by the treatment with CaCl2\mathrm{CaCl}_2 yields Ca-soap R\mathbf{R} , quantitatively. Starting with one mole of Q\mathbf{Q} , the amount of R\mathbf{R} produced in gram is __________.

[Given, atomic weight: H=1,C=12, N=14,O=16,Na=23,Cl=35,Ca=40\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Na}=23, \mathrm{Cl}=35, \mathrm{Ca}=40 ]

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JEE Advanced 2024 Paper 1 Online Chemistry - Hydrocarbons Question 1 English Explanation 1 JEE Advanced 2024 Paper 1 Online Chemistry - Hydrocarbons Question 1 English Explanation 2 JEE Advanced 2024 Paper 1 Online Chemistry - Hydrocarbons Question 1 English Explanation 3

∴1\therefore 1 mole QQ produce 32\frac{3}{2} moles RR

∴\therefore Mass of RR produce =32×606=909 g=\frac{3}{2} \times 606=909 \mathrm{~g}

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