QJEEAdv24Cha9d0: JEE Advanced 2024 Chemistry - Class 11 JEEAdv24Cha9d0 Solution: Based on VSEPR model, match the xenon compounds given in List-I …

$\mathrm{XeF}_2 \Rightarrow 2$ sigma bonds and 3 lone pairs on $\mathrm{Xe}$ , number of hybrid orbitals $=5, \mathrm{sp}^3 \mathrm{~d}$ hybridisation , geometry will be trigonal bipyramidal.

$\mathrm{P}-5$

$\mathrm{XeF}_4 \Rightarrow 4$ sigma bonds and 2 lone pairs on $\mathrm{Xe}$ , number of hybrid orbitals $=6, \mathrm{sp}^3 \mathrm{~d}^2$ hybridisation , geometry will be octahedral.

Q-3

$\mathrm{XeO}_3 \Rightarrow 3$ sigma bonds and 1 lone pairs on $\mathrm{Xe}$ , number of hybrid orbitals $=4, \mathrm{sp}^3$ hybridisation , geometry will be tetrahedral.

R-2

$\mathrm{XeO}_3 \mathrm{F}_2 \Rightarrow 5$ sigma bonds and 0 lone pairs on $\mathrm{Xe}$ , number of hybrid orbitals $=5, \mathrm{sp}^3 \mathrm{~d}$ hybridisation , geometry will be trigonal bipyramidal.

S-4