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QJEEAdv24Ch9b51: JEE Advanced 2024 Chemistry - Class 12 JEEAdv24Ch9b51 Solution: The number of moles of potassium iodide required to produce two …

The number of moles of potassium iodide required to produce two moles of P\mathbf{P} is _______.

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KI+K3[Fe(CN)6]⇌K4[Fe(CN)6]+12I2\mathrm{KI}+\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right] \rightleftharpoons \mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]+\frac{1}{2} \mathrm{I}_2

Moles of KI required =2=2

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