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QJEEA-2024-11: JEE Advanced 2024 JEEA-2024-11 Solution: Q.11  A point source S emits unpolarized light…

Q.11  A point source S emits unpolarized light uniformly in all directions. At two points A and B, the ratio π‘Ÿ = 𝐼𝐴/𝐼𝐡 of the intensities of light is 2. If a set of two polaroids having 45Β° angle between their pass-axes is placed just before point B, then the new value of π‘Ÿ will be    .


Step-by-Step Verified Solution

Solution:

  • Doppler Effect Formula:
  • f' = f (v_sound Β± v_observer) / (v_sound Β± v_source)
  • Where:
  • f' = observed frequency
  • f = source frequency
  • v_sound = speed of sound
  • v_observer = speed of observer
  • v_source = speed of source
  • Case 1 (Moving Towards):
  • f = 240 Hz
  • f' = 288 Hz
  • Let v_sound = V
  • 288 = 240 (V + v) / (V - v)
  • 288/240 = (V + v) / (V - v)
  • 6/5 = (V + v) / (V - v)
  • 6(V - v) = 5(V + v)
  • 6V - 6v = 5V + 5v
  • V = 11v
  • v = V/11
  • Case 2 (Moving Away):
  • f = 240 Hz
  • f' = n Hz
  • n = 240 (V - v) / (V + v)
  • Substitute v = V/11:
  • n = 240 (V - V/11) / (V + V/11)
  • n = 240 (10V/11) / (12V/11)
  • n = 240 (10/12)
  • n = 240 (5/6)
  • n = 40 * 5
  • n = 200

Answer:

The value of n is 200Hz

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