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QJEEAdv23Ph40d2: JEE Advanced 2023 Physics - Class 11 JEEAdv23Ph40d2 Solution: Consider both sources emitting sound. When is at and approaches …

Consider both sources emitting sound. When S2S_2 is at RR and S1S_1 approaches the detector with a speed 4 m s−14 \mathrm{~m} \mathrm{~s}^{-1} , the beat frequency measured by the detector is _________ Hz\mathrm{Hz} .

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JEE Advanced 2023 Paper 2 Online Physics - Waves Question 3 English Explanation
amp;f0=656 Hzamp;v=324 m/s\begin{aligned}& f_0=656 \mathrm{~Hz} \\\\& v=324 \mathrm{~m} / \mathrm{s}\end{aligned}

Frequency heard due to movement of (S1)\left(S_1\right)

amp;f1=(vv−us)f0amp;f1=324320×656\begin{aligned}& f_1=\left(\frac{v}{v-u_s}\right) f_0 \\\\& f_1=\frac{324}{320} \times 656\end{aligned}

And frequency heard due to movement of (S2)\left(S_2\right)

f2=656 Hzf_2=656 \mathrm{~Hz}

∴\therefore Beat frequency Δf=f1−f2=656(324320−1)\Delta f=f_1-f_2=656\left(\frac{324}{320}-1\right)

⇒\Rightarrow Δf=8.2\Delta f=8.2

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