Verified Solution • 2025–26 Session moderate

QJEEAdv23Ma53d3: JEE Advanced 2023 Mathematics - Class 11 JEEAdv23Ma53d3 Solution: Let and be two distinct common tangents to the ellipse and the…

Let T1T_1 and T2T_2 be two distinct common tangents to the ellipse E:x26+y23=1E: \frac{x^2}{6}+\frac{y^2}{3}=1 and the parabola P:y2=12xP: y^2=12 x . Suppose that the tangent T1T_1 touches PP and EE at the points A1A_1 and A2A_2 , respectively and the tangent T2T_2 touches PP and EE at the points A4A_4 and A3A_3 , respectively. Then which of the following statements is(are) true?

Multiple Choice Options

  • A The area of the quadrilateral A1A2A3A4A_1 A_2 A_3 A_4 is 35 square units
  • B The area of the quadrilateral A1A2A3A4A_1 A_2 A_3 A_4 is 36 square units
  • C The tangents T1T_1 and T2T_2 meet the xx -axis at the point (−3,0)(-3,0)
  • D The tangents T1T_1 and T2T_2 meet the xx -axis at the point (−6,0)(-6,0)

Step-by-Step Verified Solution

E:x26+y23=1, Tangent : y=m1x±6m12+3P:y2=12x, Tangent: y=m2x+3m2

For common tangent

m=m1=m2,±6m12+3=3m2⇒m=±1

⇒\Rightarrow Equation of common tangents y=x+3y=x+3 and y=−x−3y=-x-3 point of contact for parabola is (am2,2am)\left(\frac{a}{m^2}, \frac{2 a}{m}\right)

⇒A1≡(3,6),A4(3−6)

Let A2(x1,y1)⇒A_2\left(x_1, y_1\right) \Rightarrow tangent to EE is xx16+yy13=1\frac{x x_1}{6}+\frac{y y_1}{3}=1

A3A_3 is mirror image of A2A_2 in xx -axis ⇒A3(−2,−1)\Rightarrow A_3(-2,-1)

JEE Advanced 2023 Paper 1 Online Mathematics - Ellipse Question 2 English Explanation
Intersection point of T1=0T_1=0 and T2=0T_2=0 is (−3,0)(-3,0)

Area of quadrilateral A1A2A3A4=12(12+2)×5=35A_1 A_2 A_3 A_4=\frac{1}{2}(12+2) \times 5=35 square units

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