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QJEEAdv23Chc904: JEE Advanced 2023 Chemistry - Class 12 JEEAdv23Chc904 Solution: The total number of carbon atoms and heteroatoms present in one …

The total number of carbon atoms and heteroatoms present in one molecule of S\mathbf{S} is _________.

[Use : Molar mass (in gmol−1\mathrm{g} \mathrm{mol}^{-1} ): H=1,C=12, N=14,O=16,Br=80,Cl=35.5\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5
Atoms other than C\mathrm{C} and H\mathrm{H} are considered as heteroatoms]

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Compound S is

JEE Advanced 2023 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 5 English Explanation
Number of Carbon atoms + Number of Heteroatoms =51=51

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