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QJEEAdv23Cha73a: JEE Advanced 2023 Chemistry - Class 11 JEEAdv23Cha73a Solution: The value of entropy change, (in ), at is _______. [Use : Given …

The value of entropy change, Sβ−SαS_\beta-S_\alpha (in Jmol−1 K−1\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1} ), at 300 K300 \mathrm{~K} is _______.

[Use : ln⁡2=0.69\ln 2=0.69

Given : Sβ−Sα=0S_\beta-S_\alpha=0 at 0 K0 \mathrm{~K} ]

Step-by-Step Verified Solution

amp; At 1 bar amp;α⟶β\begin{aligned} & \text { At } 1 \text { bar } \\\\ & \alpha \longrightarrow \beta\end{aligned}

amp;Sα(600)o=Sα(300)o+CP(α)ln⁡600300amp; Sβ(600)o=Sβ(300)o+CP(β)ℓn600300amp; Sβ(600)o−Sα(600)o=Sβ(300)o−Sα(300)o+(CP(β)−CP(α))ℓn2amp;6−5=Sβ(300)o−Sα(300)o+1×ℓn2amp;1=Sβ(300)o−Sα(300)o+0.69\begin{aligned}& \mathrm{S}_{\alpha(600)}^{\mathrm{o}}=\mathrm{S}_{\alpha(300)}^{\mathrm{o}}+\mathrm{C}_{\mathrm{P}(\alpha)} \ln \frac{600}{300} \\\\& \mathrm{~S}_{\beta(600)}^{\mathrm{o}}=\mathrm{S}_{\beta(300)}^{\mathrm{o}}+\mathrm{C}_{\mathrm{P}(\beta)} \ell \mathrm{n} \frac{600}{300} \\\\& \mathrm{~S}_{\beta(600)}^{\mathrm{o}}-\mathrm{S}_{\alpha(600)}^{\mathrm{o}}=\mathrm{S}_{\beta(300)}^{\mathrm{o}}-\mathrm{S}_{\alpha(300)}^{\mathrm{o}}+\left(\mathrm{C}_{\mathrm{P}(\beta)}-\mathrm{C}_{\mathrm{P}(\alpha)}\right) \ell \mathrm{n} 2 \\\\& 6-5=\mathrm{S}_{\beta(300)}^{\mathrm{o}}-\mathrm{S}_{\alpha(300)}^{\mathrm{o}}+1 \times \ell \mathrm{n} 2 \\\\& 1=\mathrm{S}_{\beta(300)}^{\mathrm{o}}-\mathrm{S}_{\alpha(300)}^{\mathrm{o}}+0.69\end{aligned}

So Sβ(300)o−Sα(300)o=0.31\mathrm{S}_{\beta(300)}^{\mathrm{o}}-\mathrm{S}_{\alpha(300)}^{\mathrm{o}}=0.31

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