Verified Solution • 2025–26 Session moderate

QJEEAdv23Ch3368: JEE Advanced 2023 Chemistry - Class 12 JEEAdv23Ch3368 Solution: In the scheme given below, and , respectively, are

In the scheme given below, X\mathbf{X} and Y\mathbf{Y} , respectively, are

JEE Advanced 2023 Paper 1 Online Chemistry - d and f Block Elements Question 1 English

Multiple Choice Options

  • A CrO42−\mathrm{CrO}_4{ }^{2-} and Br2\mathrm{Br}_2
  • B MnO42−\mathrm{MnO}_4{ }^{2-} and Cl2\mathrm{Cl}_2
  • C MnO4−\mathrm{MnO}_4{ }^{-} and Cl2\mathrm{Cl}_2
  • D MnSO4\mathrm{MnSO}_4 and HOCl\mathrm{HOCl}

Step-by-Step Verified Solution

MnCl2⟶NaOH(aq)Mn(OH2)(P)+NaCl(Q)\mathrm{MnCl}_2 \stackrel{\mathrm{NaOH}(\mathrm{aq})}{\longrightarrow} \underset{(\mathrm{P})}{\mathrm{Mn}\left(\mathrm{OH}_2\right)}+\underset{(\mathrm{Q})}{\mathrm{NaCl}}

Mn(OH)2⟶ aq. H2SO4PbO2( excess )MnO4−(X)+Pb2+\mathrm{Mn}(\mathrm{OH})_2 \underset{\mathrm{PbO}_2(\text { excess })}{\stackrel{\text { aq. } \mathrm{H}_2 \mathrm{SO}_4}{\longrightarrow}} \underset{(\mathrm{X})}{\mathrm{MnO}_4^{-}}+\mathrm{Pb}^{2+}

NaClMnO(OH)2 conc. H2SO4 warm Cl2(Y)\mathrm{NaCl} \frac{\mathrm{MnO}(\mathrm{OH})_2}{\text { conc. } \mathrm{H}_2 \mathrm{SO}_4 \text { warm }} \underset{(\mathrm{Y})}{\mathrm{Cl}_2}

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