Verified Solution • 2025–26 Session moderate

QJEEAdv22Ph6d39: JEE Advanced 2022 Physics - Class 12 JEEAdv22Ph6d39 Solution: A charge is surrounded by a closed surface consisting of an…

A charge $q$ is surrounded by a closed surface consisting of an inverted cone of height $h$ and base radius $R$ , and a hemisphere of radius $R$ as shown in the figure. The electric flux through the conical surface is $\frac{n q}{6 \epsilon_{0}}$ (in SI units). The value of $n$ is _______.

JEE Advanced 2022 Paper 2 Online Physics - Electrostatics Question 20 English

Step-by-Step Verified Solution

JEE Advanced 2022 Paper 2 Online Physics - Electrostatics Question 20 English Explanation

Sol. From Gauss law,

ϕ_{hemisphere} + ϕ_{Cone} = \frac{q}{ε_{0}}

............(1)

Total flux produced from

\mathrm{q}

in

\alpha

angle

ϕ = \frac{q}{2 ε_{0}} [1 - \cos α]

For hemisphere,

\alpha=\frac{\pi}{2}

ϕ_{hemisphere} = \frac{q}{2 ε_{0}}

From equation (1)

\begin{aligned} = \frac{q}{2 ε_{0}} + ϕ_{cone} = \frac{q}{ε_{0}} \\ ϕ_{cone} = \frac{q}{2 ε_{0}} \\ \frac{4 q}{6 ε_{0}} = \frac{q}{2 ε_{0}} \\ n = 3 \end{aligned}

Related Learning Resources & Exam Preparation

JEE Advanced PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring