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QJEEAdv22Ph49d3: JEE Advanced 2022 Physics - Class 11 JEEAdv22Ph49d3 Solution: On a frictionless horizontal plane, a bob of mass is attached…

On a frictionless horizontal plane, a bob of mass m=0.1 kgm=0.1 \mathrm{~kg} is attached to a spring with natural length l0=0.1 ml_{0}=0.1 \mathrm{~m} . The spring constant is k1=0.009 Nm−1k_{1}=0.009 \,\mathrm{Nm}^{-1} when the length of the spring l>l_{0} and is k2=0.016 Nm−1k_{2}=0.016 \,\mathrm{Nm}^{-1} when l < l_{0} . Initially the bob is released from l=l= 0.15 m0.15 \mathrm{~m} . Assume that Hooke's law remains valid throughout the motion. If the time period of the full oscillation is T=(nπ)sT=(n \pi) s , then the integer closest to nn is __________.

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Time period of oscillation

=T1+T2=πmK1+πmK2=π0.10.009+π0.10.016=π0.3+π0.4=π(0.4+0.3)0.12=70π12=5.83π seconds ≃6π seconds 

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