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QJEEAdv22Ma389a: JEE Advanced 2022 Mathematics - Class 11 JEEAdv22Ma389a Solution: Let be a quadrilateral in a plane, where and . If and , then…

Let PQRSP Q R S be a quadrilateral in a plane, where

QR=1,∠PQR=∠QRS=70∘,∠PQS=15∘Q R=1, \angle P Q R=\angle Q R S=70^{\circ}, \angle P Q S=15^{\circ} and ∠PRS=40∘\angle P R S=40^{\circ} .

If ∠RPS=θ∘,PQ=α\angle R P S=\theta^{\circ}, P Q=\alpha and PS=βP S=\beta , then the interval(s) that contain(s) the value of

4αβsin⁡θ∘4 \alpha \beta \sin \theta^{\circ} is/are

Multiple Choice Options

  • A (0,2)(0, \sqrt{2})
  • B (1,2)(1,2)
  • C (2,3)(\sqrt{2}, 3)
  • D (22,32)(2 \sqrt{2}, 3 \sqrt{2})

Step-by-Step Verified Solution

JEE Advanced 2022 Paper 2 Online Mathematics - Trigonometric Functions & Equations Question 4 English Explanation

Applying sine rule in △PQR\triangle P Q R ,

αsin⁡30∘=1sin⁡80∘⇒α=12sin⁡80∘

Applying sine rule in △PRS\triangle P R S ,

βsin⁡40∘=1sin⁡θ⇒βsin⁡θ=sin⁡40∘

From (i) and (ii),

4αβsin⁡θ=4⋅12sin⁡80∘⋅sin⁡40∘=1cos⁡40∘

Using cos⁡0∘=1,cos⁡30∘=32,cos⁡45∘=12\cos 0^{\circ}=1, \cos 30^{\circ}=\frac{\sqrt{3}}{2}, \cos 45^{\circ}=\frac{1}{\sqrt{2}} and cos⁡60∘=12\cos 60^{\circ}=\frac{1}{2}

Only Options (A) and (B) are correct.

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