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QJEEAdv22Chd571: JEE Advanced 2022 Chemistry - Class 12 JEEAdv22Chd571 Solution: The compound(s) which react(s) with to give boron nitride (BN)…

The compound(s) which react(s) with NH3\mathrm{NH}_{3} to give boron nitride (BN) is(are)

Multiple Choice Options

  • A B\mathrm{B}
  • B B2H6\mathrm{B}_{2} \mathrm{H}_{6}
  • C B2O3\mathrm{B}_{2} \mathrm{O}_{3}
  • D HBF4\mathrm{HBF}_{4}

Step-by-Step Verified Solution

The compound(s) which react with NH3\mathrm{NH}_3 to form Boron nitride (BN)(\mathrm{BN}) is/are:

(A) Amorphous B+NH3⟶ Very high  Tempreature BN+H2\mathrm{B}+\mathrm{NH}_3 \underset{\text { Tempreature }}{\stackrel{\text { Very high }}{\longrightarrow}} \mathrm{BN}+\mathrm{H}_2

(B) B2H6+NH3⟶ High Temp. (BN)x\mathrm{B}_2 \mathrm{H}_6+\mathrm{NH}_3 \stackrel{\text { High Temp. }}{\longrightarrow}(\mathrm{BN})_{\mathrm{x}}

(C) B2O3+2NH3⟶900∘C2BN+3H2O\mathrm{B}_2 \mathrm{O}_3+2 \mathrm{NH}_3 \stackrel{900^{\circ} \mathrm{C}}{\longrightarrow} 2 \mathrm{BN}+3 \mathrm{H}_2 \mathrm{O}

(D) HBF4+NH3⟶[NH4⊕][BF4⊖]\mathrm{HBF}_4+\mathrm{NH}_3 \longrightarrow\left[\mathrm{NH}_4^{\oplus}\right]\left[\mathrm{BF}_4^{\ominus}\right]

Hence, (A,B,C)(A, B, C) are correct

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