QJEEAdv22Chc7b1: JEE Advanced 2022 Chemistry - Class 12 JEEAdv22Chc7b1 Solution: Considering the following reaction sequence, the correct…

Question

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Considering the following reaction sequence,

JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 12 English

the correct option(s) is(are)

A $\mathbf{P}=\mathrm{H}_{2} / \mathrm{Pd}$ , ethanol $\mathbf{R}=\mathrm{NaNO}_{2} / \mathrm{HCl}$ $\mathbf{U}=1 . \mathrm{H}_{3} \mathrm{PO}_{2}$ 2. $\mathrm{KMnO}_{4}-\mathrm{KOH}$ , heat
B https://ik.imagekit.io/novatra/photos/f92cb4e3fe6935e5cfa119f7b63c260e428f02342c2ef91df42f4883918682ba.webp
C https://ik.imagekit.io/novatra/photos/89c46774be36a44419fd8968580ad30f74e5f4ba73fb3ed1b1464ebf99740992.webp
D https://ik.imagekit.io/novatra/photos/a51be0e99de3b3c32da7e3dcd3b468e774e404dc22d97863f9d9a40c6345f03d.webp

Accepted Answer

JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 12 English Explanation

$\to$ P may be $\to$ H₂/Pd, ethanol; Sn/HCl

$\to$ R may be $\to$ NaNO₂/HCl; HNO₂

$\to$ U may be $\to$ (i) H₃PO₂, (ii) KMnO₄ - KOH, $\Delta$ or (i) CH₃ - CH₂ - OH, (ii) KMnO₄ - KOH, $\Delta$

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