Verified Solution • 2025–26 Session moderate

QJEEAdv22Ch6313: JEE Advanced 2022 Chemistry - Class 12 JEEAdv22Ch6313 Solution: Match the compounds in LIST-I with the observations in LIST-II, …

Match the compounds in LIST-I with the observations in LIST-II, and choose the correct option.

List-I List-II
(I) Aniline
(P) Sodium fusion extract of the compound on boiling with FeSO4\mathrm{FeSO}_{4} , followed by acidification with conc. H2SO4\mathrm{H}_{2} \mathrm{SO}_{4} , gives Prussian blue color.
(II) oo -Cresol (Q) Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
(III) Cysteine
(R) Addition of the compound to a saturated solution of NaHCO3\mathrm{NaHCO}_{3} results in effervescence.
(IV) Caprolactam
(S) The compound reacts with bromine water to give a white precipitate.
(T) Treating the compound with neutral FeCl3\mathrm{FeCl}_{3} solution produces violet color.

Multiple Choice Options

  • A I→P,Q\mathrm{I} \rightarrow \mathrm{P}, \mathrm{Q} ; II →S;III→Q,R\rightarrow \mathrm{S} ; \mathrm{III} \rightarrow \mathrm{Q}, \mathrm{R} ; IV →P\rightarrow \mathrm{P}
  • B I→P\mathrm{I} \rightarrow \mathrm{P} ; II →R\rightarrow \mathrm{R} , S\mathrm{S} ; III →R\rightarrow \mathrm{R} ; IV→Q,S\mathrm{IV} \rightarrow \mathrm{Q}, \mathrm{S}
  • C I→Q,S\mathrm{I} \rightarrow \mathrm{Q}, \mathrm{S} ; II →P,T\rightarrow \mathrm{P}, \mathrm{T} ; III →P\rightarrow \mathrm{P} ; IV →S\rightarrow \mathrm{S}
  • D I→P\mathrm{I} \rightarrow \mathrm{P} , S; II →T\rightarrow \mathrm{T} ; III →Q,R\rightarrow \mathrm{Q}, \mathrm{R} ; IV→P\mathrm{IV} \rightarrow \mathrm{P}

Step-by-Step Verified Solution

(I) Aniline has N\mathrm{N} atoms hence gives prussian blue colour in Sodium fusion extract test. Aniline also gives white precipitate with Bromine water.

(II) O\mathbf{O} -Cresol has phenolic group hence gives violet colour complex with netural FeCl3\mathrm{FeCl}_3 .

(III) Cysteine has 'S' atom, hence gives blood red color when odium S fusion extract of this compound is treated with sodium nitroprusside.

(IV) Caprolactam has N\mathrm{N} atom, hence sodium extract of this compound gives prussian blue color.

Related Learning Resources & Exam Preparation