QJEEAdv21Ph69cf: JEE Advanced 2021 Physics - Class 11 JEEAdv21Ph69cf Solution: The value of T R T 0 is

Question

Verified Solution • 2025–26 Session moderate

The value of

\frac{T_{R}}{T_{0}}

is

Accepted Answer

γ = \frac{3}{2}

T_{0} {V_{0}}^{\frac{3}{2} - 1} = T_{R} \times {(\frac{V_{0}}{2})}^{\frac{3}{2} - 1}

\frac{T_{R}}{T_{0}} = \sqrt{2}

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