QJEEAdv21Ph66b6: JEE Advanced 2021 Physics - Class 12 JEEAdv21Ph66b6 Solution: In the circuit shown below, the switch S is connected to…

Question

Verified Solution • 2025–26 Session moderate

In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q₁

μ

C. Then S is switched to position Q. After a long time, the charge on the capacitor is q₂

μ

C.

The magnitude of q₂ is ________________.

Accepted Answer

Switch at position Q

JEE Advanced 2021 Paper 1 Online Physics - Capacitor Question 8 English Explanation

V_{A} - 1 . i_{2} + 2 - 2 i_{2} = V_{A}

3 i_{2} = 2

\Rightarrow i_{2} = \frac{2}{3} A

Now,

V_{A} - i_{2} \times 1 = V_{B}

V_{A} - V_{B} = i_{2} \times 1 = \frac{2}{3} V

Potential difference across capacitor,

Δ V = \frac{2}{3} V

∴

Charge on capacitor,

q_{2} = C Δ V = 1 \times \frac{2}{3} = 0.67 μ C

Step-by-Step Verified Solution