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QJEEAdv21Ma6130: JEE Advanced 2021 Mathematics - Class 12 JEEAdv21Ma6130 Solution: Three numbers are chosen at random, one after another with…

Three numbers are chosen at random, one after another with replacement, from the set S = {1, 2, 3, ......, 100}. Let p1 be the probability that the maximum of chosen numbers is at least 81 and p2 be the probability that the minimum of chosen numbers is at most 40.

The value of 6254p1 is ___________.

Step-by-Step Verified Solution

p1 = 1 − p (all 3 numbers are ≤ 80)

=1−(80100)3=125−64125=61125

So, 625p14=6254×61125=54×61=76.25

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