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QJEEAdv21Cheff1: JEE Advanced 2021 Chemistry - Class 11 JEEAdv21Cheff1 Solution: The value of y is ________.

The value of y is ________.

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JEE Advanced 2021 Paper 1 Online Chemistry - Hydrocarbons Question 18 English Explanation
60+32+8=10060+32+8=100

The value of Y=0.032×100=3.2\mathrm{Y}=0.032 \times 100=3.2

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