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QJEEAdv21Ch9ade: JEE Advanced 2021 Chemistry - Class 12 JEEAdv21Ch9ade Solution: Reaction of x g of Sn with HCl quantitatively produced a salt.…

Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).

(Use Molar masses (in g mol −- 1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively).

The value of x is _________.

Step-by-Step Verified Solution

JEE Advanced 2021 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 23 English Explanation

Mass of organic salt produced (aniline) = 1.29 g

Molar mass of organic salt (aniline)

= 12 × 6 + 1 × 8 + 14 × 1 + 35 × 1

= 72 + 8 + 14 + 35

= 129 g/mol

Moles of organic salt=Mass of organic saltMolar massMoles\ of\ organic\ salt=\frac{Mass\ of\ organic\ salt}{Molar\ mass}

=1.29129=0.01 mol=\frac{1.29}{129} =0.01\ mol

From reaction 1 moles of salt is produced from 3 mole of Sn. So, 0.01 mole of organic salt is produced by 0.03 mole Sn. Atomic mass of Sn = 119 g mol−1

Mass of Sn = x = mole of Sn × Molar mass

x = 0.03 × 119 ⇒\Rightarrow x = 3.57 g

The value of x is 3.57

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