Verified Solution • 2025–26 Session moderate

QJEEAdv21Ch1c1c: JEE Advanced 2021 Chemistry - Class 11 JEEAdv21Ch1c1c Solution: Correct match of the C-H bonds (shown in bold) in Column J with …

Correct match of the C-H bonds (shown in bold) in Column J with their BDE in Column K is

Column J
Molecule
Column K
BDE (kcal mol−1mo{l^{ - 1}} )
(P) H-CH( CH3C{H_3} ) 2_2 (i) 132
(Q) H-CH 2_2 Ph (ii) 110
(R) H-CH=CH 2_2 (iii) 95
(S) H-C ≡\equiv CH (iv) 88

Multiple Choice Options

  • A P - iii, Q - iv, R - ii, S - i
  • B P - i, Q - ii, R - iii, S - iv
  • C P - iii, Q - ii, R - i, S - iv
  • D P - ii, Q - i, R - iv, S - ii

Step-by-Step Verified Solution

A more stable radical means lesser the bond dissociation energy.

Radicals formed are

JEE Advanced 2021 Paper 2 Online Chemistry - Basics of Organic Chemistry Question 24 English Explanation

Radical formed from Q (PhCH2 −- H) is most stable due to resonance.

Stability of free radical decreases with increase in % s-character.

P radical →\to sp3 →\to % s-character 25%

R radical →\to sp2 →\to % s-character 33%

S radical →\to sp →\to % s-character 50%

Thus, order of stability of free radical is

Q > P > R > S

Order of bond dissociation energy is

S > R > P > Q

Related Learning Resources & Exam Preparation