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QJEEAdv20Chbf94: JEE Advanced 2020 Chemistry - Class 12 JEEAdv20Chbf94 Solution: The structure of a peptide is given below. If the absolute…

The structure of a peptide is given below.

JEE Advanced 2020 Paper 2 Offline Chemistry - Biomolecules Question 16 English
If the absolute values of the net charge of the peptide at pH\mathrm{pH} =2=2 , pH=6\mathrm{pH}=6 , and pH=11\mathrm{pH}=11 are ∣Z1∣,∣Z2∣\left|Z_1\right|,\left|Z_2\right| , and ∣Z3∣\left|Z_3\right| , respectively, then what is ∣Z1∣+∣Z2∣+∣Z3∣\left|Z_1\right|+\left|Z_2\right|+\left|Z_3\right| ?

Step-by-Step Verified Solution

At pH = 2,

There are two −- NH2 group, and + 1 charge on each group because all amino groups exist in the form of −- NH 3⊕_3^ \oplus .

Therefore, |Z1| = 2.

At pH = 6,

NH2 of lysine (+ 1) (pH = 9.47) and COOH ( −- 1) of glutamic (pH = 3.08) acid, so because of dipolar ion exists, therefore |Z2| = 0.

At pH = 11,

COOH of glutamic acid has ( −- 1), COOH of lysine ( −- 1) and OH of phenol ( −- 1).

Therefore, |Z3| = | −- 3| = 3 (All COOH and OH exist in the form of −- COO −- and −- O −- ).

∴\therefore |Z1| + |Z2| + |Z3| = 2 + 0 + 3 = 5

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