QJEEAdv20Ch7c65: JEE Advanced 2020 Chemistry - Class 11 JEEAdv20Ch7c65 Solution: Choose the correct statement(s) among the following :

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QJEEAdv20Ch7c65: JEE Advanced 2020 Chemistry - Class 11 JEEAdv20Ch7c65 Solution: Choose the correct statement(s) among the following :

Choose the correct statement(s) among the following :

Multiple Choice Options

A SnCl2 . 2H2O is a reducing agent.
B SnO2 reacts with KOH to form K2[Sn(OH)6].
C A solution of PbCl2 in HCl contains Pb2+ and Cl− ions.
D The reaction of Pb3O4 with hot dilute nitric acid to give PbO2 is a redox reaction.

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Accepted Answer

Sn²⁺ of stannous chloride dihydrate (SnCl₂ . 2H₂O) tends to convert into Sn⁴⁺.

Hence, statement (a) is correct.

(b) SnO₂ reacts with KOH and gives K₂SnO₃ . 3H₂O or K₂[Sn(OH)₆] because it is amphoteric in nature.

S n O_{2} + K O H \overset{}{⟶} K_{2} S n O_{3} + H_{2} O

or

K_{2} [S n (O H)_{6}]

Hence, statement (b) is correct.

(c) In conc. HCl, PbCl₂ exists as chloroplumbous acid, H₂[PbCl₄]

\overset{I I}{P b C l_{2}} + 2 H C l \overset{}{⟶} \overset{I I}{H_{2} [P b C l_{4}]}

Hence, statement (c) is incorrect.

(d) Pb₃O₄ is a mixture of

(2 \overset{+ 2}{P b O} + {P b O}_{2}^{+ 4})

P b_{3} O_{4} + 4 H N O_{3} \overset{}{⟶} \overset{+ 2}{2 P b {(N O_{3})}_{2}} + \overset{+ 4}{P b O_{2}} + 2 H_{2} O

It is not a redox reaction. Thus, the statement (d) is incorrect.

QJEEAdv20Ch7c65: JEE Advanced 2020 Chemistry - Class 11 JEEAdv20Ch7c65 Solution: Choose the correct statement(s) among the following :

Multiple Choice Options

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