Verified Solution • 2025–26 Session moderate

QJEEAdv20Ch0d43: JEE Advanced 2020 Chemistry - Class 11 JEEAdv20Ch0d43 Solution: Consider the reaction, A B at 1000 K. At time t', the…

Consider the reaction,

A ⇌\rightleftharpoons B

at 1000 K. At time t', the temperature of the system was increased to 2000 K and the system was allowed to reach equilibrium. Throughout this experiment the partial pressure of A was maintained at 1 bar. Given, below is the plot of the partial pressure of B with time. What is the ratio of the standard Gibbs energy of the reaction at 1000 K to that at 2000 K?

JEE Advanced 2020 Paper 1 Offline Chemistry - Chemical Equilibrium Question 4 English

Step-by-Step Verified Solution

Given : Image

Using ΔG=ΔGo+RTln⁡Kp\Delta G = \Delta {G^o} + RT\ln {K_p}

At equilibrium : ΔGo=−RTln⁡Kp\Delta {G^o} = - RT\ln {K_p}

ΔG10=−RT1ln⁡Kp1\Delta G_1^0 = - R{T_1}\ln {K_{p1}} ... (i)

ΔG20=−RT2ln⁡Kp2\Delta G_2^0 = - R{T_2}\ln {K_{p2}} ...(ii)

From Eqs. (i) and (ii),

ΔG1oΔG2o=T1T2×ln⁡Kp1ln⁡Kp2{{\Delta G_1^o} \over {\Delta G_2^o}} = {{{T_1}} \over {{T_2}}} \times {{\ln K{p_1}} \over {\ln K{p_2}}}

=10002000×ln⁡(10)ln⁡(100)=14=0.25= {{1000} \over {2000}} \times {{\ln (10)} \over {\ln (100)}} = {1 \over 4} = 0.25

Related Learning Resources & Exam Preparation