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QJEEAdv19Ph1f93: JEE Advanced 2019 Physics - Class 11 JEEAdv19Ph1f93 Solution: A block of weight 100 N is suspended by copper and steel wires…

A block of weight 100 N is suspended by copper and steel wires of same cross-sectional area 0.5 cm2 and length 3 m and 1 m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30∘ and 60∘, respectively. If elongation in copper wire is (Δlc) and elongation in steel wire is (Δls), then the ratio ΔlcΔls is .............. .

[Young's modulus for copper and steel are 1 × 1011 N/m2 and 2 × 1011 N/m2 respectively.]

JEE Advanced 2019 Paper 1 Offline Physics - Properties of Matter Question 29 English

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JEE Advanced 2019 Paper 1 Offline Physics - Properties of Matter Question 29 English Explanation

Ts2=Tc32

Ts=3Tc

Δl=TlAy

∴ ΔlcΔls=(TcTs)(lcls)(YsYc)

=(13)(31)(2×10111×1011)=2.00

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