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QJEEAdv19Ma8ad0: JEE Advanced 2019 Mathematics - Class 11 JEEAdv19Ma8ad0 Solution: Let AP(a; d) denote the set of all the terms of an infinite…

Let AP(a; d) denote the set of all the terms of an infinite arithmetic progression with first term a and common difference d > 0. If AP(1;3)∩AP(2;5)∩AP(3;7) = AP(a ; d), then a + d equals ..............

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Given that, AP(a ; d) denote the set of all the terms of an infinite arithmetic progression with first term 'a' and common difference d > 0.

Now, let mth term of first progression

AP(1;3)=1+(m−1)3=3m−2 .... (i)

and nth term of progression

AP(2;5)=2+(n−1)5=5m−3 .... (ii)

and rth term of third progression

AP(3;7)=3+(r−1)7=7m−4 .... (iii) are equal.

Then, 3m−2=5n−3=7r−4

Now, for AP(1;3)∩AP(2;5)∩AP(3;7),

the common terms of first and second progressions, m=5n−13

⇒ n = 2, 5, 11, ...

and the common terms of second and the third progressions,

r=5n+17 ⇒ n = 4, 11, ....

Now, the first common term of first, second and third progressions (when n = 11), so

a = 2 + (11 - 1)5 = 52

and d = LCM (3, 5, 7) = 105

So, AP(1;3)∩AP(2;5)∩AP(3;7) = AP(52; 105)

So, a = 52 and d = 105

⇒ a + d = 157.00

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