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QJEEAdv19Ch6d90: JEE Advanced 2019 Chemistry - Class 11 JEEAdv19Ch6d90 Solution: The amount of water produced (in g) in the oxidation of 1 mole…

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO₃ to a compound with the highest oxidation state of sulphur is ..............

(Given data : Molar mass of water = 18 g mol^{$-$ 1})

Step-by-Step Verified Solution

When rhombic sulphur (S₈) is oxidised by conc. HNO₃ then H₂SO₄ is obtained and NO₂ gas is released.

S_{8} + 48 H N O_{3} \overset{}{⟶} 8 H_{2} S O_{4} + 48 N O_{2} + 16 H_{2} O

1 mole of rhombic sulphur produces = 16 moles of H₂O

∴

Mass of water = 16

\times

18 (molar mass of H₂O) = 288 g

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